Question

question 2 1 pts 1200 ft. 48° flight 4358 took off from the dfw airport at an elevation of 48°. if the airplane has been traveling for 1200 ft., approximately how far above the ground is the airplane? 1614 891 802

Explanation:

Step1: Identify the trigonometric ratio

We have a right - triangle where the hypotenuse is \(1200\) ft and we need to find the opposite side \(x\) with respect to the angle \(48^{\circ}\). The sine ratio is \(\sin\theta=\frac{\text{opposite}}{\text{hypotenuse}}\). So, \(\sin(48^{\circ})=\frac{x}{1200}\).

Step2: Solve for \(x\)

Multiply both sides of the equation \(\sin(48^{\circ})=\frac{x}{1200}\) by \(1200\). We get \(x = 1200\times\sin(48^{\circ})\).
Using a calculator, \(\sin(48^{\circ})\approx0.7431\). Then \(x=1200\times0.7431 = 891.72\approx891\).

Answer:

891