Question

question 8
2 points
table 18.1
antibody titer
\tday 1\tday 7\tday 14\tday 21
patient a\t0\t0\t256\t512
patient b\t128\t256\t512\t1024
patient c\t0\t0\t0\t0
patient d\t128\t128\t128\t128
in table 18.1, who probably has the disease?
a patients a and b
b patients a and c
c patients a and d
d patients b and c
e patients c and d

Explanation:

Antibody titers rise in response to active infection. Patient A shows increasing titers (0→0→256→512), indicating a developing immune response. Patient B has consistently rising titers (128→256→512→1024), also signifying active infection. Patient C has no antibodies, and Patient D has stable titers (likely pre-existing immunity, not active disease). Thus, Patients A and B probably have the disease.

Answer:

A. Patients A and B