Question

question 7 (1 point)
could you use sas to prove ( \triangle cba cong \triangle ced ). explain.
( \bigcirc ) a yes, vertical angles
( \bigcirc ) b yes, we could also use sss
( \bigcirc ) c yes, because of the right angles
( \bigcirc ) d no, we only know one side so vertical angles is no help for sas

Explanation:

Step1: Recall SAS (Side - Angle - Side) criteria

SAS requires two sides and the included angle of one triangle to be equal to two sides and the included angle of another triangle.

Step2: Analyze the given information

We know that \( \angle A=\angle D = 90^{\circ}\) (right angles). Also, \(AC = CD\) (given as marked). The vertical angles \(\angle BCA=\angle ECD\). But for SAS, we need two sides. Here, we only know one pair of sides (\(AC = CD\)). Just having vertical angles (which are equal) is not sufficient as we lack the second pair of sides for the SAS criterion.

Answer:

D. no, we only know one side so vertical angles is no help for SAS