Question

question 1 (1 point)
in which of the following scenarios was the most net work done?
o a a net force of 10 n is applied to an object as it is displaced 1 m.
o b an objects kinetic energy is increased by 20 j.
o c a 5 kg objects velocity is increased from 1 m/s to 3 m/s.
o d a net force of 5 n is applied to an object as it is displaced 5 m.
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Explanation:

Step1: Calculate work for option a

Using the work formula \(W = Fd\), where \(F = 10N\) and \(d = 1m\).
\(W_a=10\times1 = 10J\)

Step2: Calculate work for option b

By the work - energy theorem, \(W=\Delta K\). Given \(\Delta K = 20J\), so \(W_b = 20J\)

Step3: Calculate work for option c

Using the kinetic energy formula \(K=\frac{1}{2}mv^{2}\). Initial \(v_i = 1m/s\), final \(v_f=3m/s\), \(m = 5kg\).
\(\Delta K=\frac{1}{2}m(v_f^{2}-v_i^{2})=\frac{1}{2}\times5\times(3^{2}-1^{2})=\frac{1}{2}\times5\times(9 - 1)=20J\). By work - energy theorem \(W_c=\Delta K = 20J\)

Step4: Calculate work for option d

Using \(W = Fd\), \(F = 5N\), \(d = 5m\)
\(W_d=5\times5=25J\)

Answer:

D. A net force of 5 N is applied to an object as it is displaced 5 m.