Question

question 9 (1 point)
using the appropriate special triangle, determine θ if 0° ≤ θ ≤ 90° for cosθ = √3/2.
a) 60°
b) 90°
c) 30°
d) 45°

Explanation:

Step1: Recall special angles

We know that for special angles in the range \(0^{\circ}\leq\theta\leq90^{\circ}\), \(\cos30^{\circ}=\frac{\sqrt{3}}{2}\), \(\cos45^{\circ}=\frac{\sqrt{2}}{2}\), \(\cos60^{\circ}=\frac{1}{2}\), \(\cos90^{\circ} = 0\).

Answer:

C. \(30^{\circ}\)