Question

question 7 (1 point)
an object is thrown upward with a speed of 12 m/s on the surface of planet x where the acceleration due to gravity is 1.5 m/s2. how long does it take for the object to reach the maximum height?
8.0 s
11 s
14 s
16 s

Explanation:

Step1: Identify the kinematic equation

Use the equation \(v = v_0+at\). At maximum height, \(v = 0\). The initial velocity \(v_0=12\ m/s\), and the acceleration \(a=- 1.5\ m/s^2\) (negative because it acts against the motion).

Step2: Solve for time \(t\)

Rearrange the equation \(v = v_0+at\) to \(t=\frac{v - v_0}{a}\). Substitute \(v = 0\), \(v_0 = 12\ m/s\), and \(a=-1.5\ m/s^2\) into the formula: \(t=\frac{0 - 12}{-1.5}\).
Calculate \(\frac{- 12}{-1.5}=8\ s\).

Answer:

8.0 s