Question

question
perform the operation.
\\((-3x^2 + 3x - 8) + (6x^2 - 4x)\\)

Explanation:

Step1: Remove parentheses

To add the two polynomials, we first remove the parentheses. Since there is a plus sign in front of the second parentheses, the signs of the terms inside remain the same. So we have:
\(-3x^{2}+3x - 8+6x^{2}-4x\)

Step2: Combine like terms

• For the \(x^{2}\) terms: \(-3x^{2}+6x^{2}=(- 3 + 6)x^{2}=3x^{2}\)
• For the \(x\) terms: \(3x-4x=(3 - 4)x=-x\)
• The constant term remains \(-8\)

Combining these results, we get \(3x^{2}-x - 8\)

Answer:

\(3x^{2}-x - 8\)