Question

question 3(multiple choice worth 4 points)
(06 02 mc)
a cylindrical piece of iron pipe is shown below. the wall of the pipe is 1.25 inch thick.
what is the approximate inside volume of the pipe?
○ 88 cubic inches
○ 49 cubic inches
○ 142 cubic inches
○ 154 cubic inches

Explanation:

Step1: Calculate inner radius

The outer diameter is \(6\) inches, so the outer radius \(R=\frac{6}{2}=3\) inches. The thickness is \(1.25\) inches, so the inner radius \(r = 3 - 1.25=1.75\) inches.

Step2: Use cylinder volume formula

The volume formula for a cylinder is \(V=\pi r^{2}h\). Here, \(h = 16\) inches. Substitute \(r = 1.75\) and \(h = 16\) into the formula: \(V=\pi\times(1.75)^{2}\times16\).
First, calculate \((1.75)^{2}=3.0625\). Then \(V=\pi\times3.0625\times16\).
\(3.0625\times16 = 49\). So \(V = 49\pi\approx49\times 3.14 = 154\) (using \(\pi\approx3.14\)).

Answer:

154 cubic inches