Question

question 2(multiple choice worth 1 points)
(01.06 mc)
the equation for the area of a trapezoid is ( a=\frac{1}{2} hleft(b_1+b_2
ight) ).
if ( a = 18, b_1 = 5 ), and ( b_2 = 7 ), what is the height of the trapezoid?
( \bigcirc h = 1.5 )
( \bigcirc h = 3 )
( \bigcirc h = 6 )
( \bigcirc h = 7 )

Explanation:

Step1: Substitute the given values into the formula

Given \(A = 18\), \(b_1=5\), \(b_2 = 7\), substitute into \(A=\frac{1}{2}h(b_1 + b_2)\). So \(18=\frac{1}{2}h(5 + 7)\).

Step2: Simplify the equation

First, calculate \(5 + 7=12\). The equation becomes \(18=\frac{1}{2}h\times12\). Since \(\frac{1}{2}\times12 = 6\), the equation is \(18 = 6h\).

Step3: Solve for \(h\)

Divide both sides of the equation \(18 = 6h\) by \(6\). We get \(h=\frac{18}{6}\).

Answer:

\(h = 3\)