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question 7 (mandatory) (1 point) in the dialysis bag experiment, what do you think will happen if we reverse the two solutions between the sac and the beaker for sac 4 (meaning sac 4 is filled with distilled water and beaker 4 is 40% sucrose)? will the sac gain or lose weight? water will move into the sac even more; the sac will gain weight water will not move because sac membrane is impermeable to sucrose; the sac will have no change in weight water will move out of the sac; the sac lose weight water will not move because sucrose can move across the sac membrane to equilibrium; the sac will have no change in weight
In a dialysis bag experiment, we consider osmosis (movement of water across a semi - permeable membrane). The sac has 40% sucrose solution and the beaker has distilled water initially, but when reversed, the sac has distilled water and the beaker has 40% sucrose. The sac membrane is semi - permeable (usually impermeable to sucrose in typical dialysis bag setups for osmosis experiments). Water moves from an area of lower solute concentration (sac, distilled water) to higher solute concentration (beaker, 40% sucrose) by osmosis. So water moves out of the sac, and as a result, the sac loses weight.
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water will move out of the sac; the sac lose weight