Question

question
in (\triangle hij), the measure of (angle j = 90^{circ}), (ji = 7), (ih = 25), and (hj = 24). what ratio represents the sine of (angle i)?
answer attempt 1 out of 2
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Explanation:

Step1: Recall the definition of sine in a right - triangle

In a right - triangle, \(\sin\theta=\frac{\text{opposite}}{\text{hypotenuse}}\). For \(\angle I\) in \(\triangle HIJ\) with \(\angle J = 90^{\circ}\), the side opposite \(\angle I\) is \(HJ\), and the hypotenuse is \(IH\).

Step2: Substitute the given values into the sine formula

We know that \(HJ = 24\) and \(IH=25\). Using the formula \(\sin I=\frac{\text{opposite}}{\text{hypotenuse}}\), we substitute the values: \(\sin I=\frac{HJ}{IH}\).

Answer:

\(\frac{24}{25}\)