Question

question #7
a frequency distribution is to be constructed with the following data. five classes are to be constructed with a class width of 9. determine the upper - class limit for the first class.
92, 82, 76, 83, 56, 57, 60, 98, 83, 95, 89, 76, 57, 94, 70, 69, 86, 64, 69, 56, 57, 63, 55, 63, 75, 98
55
64
54
63

Explanation:

Step1: Find the minimum value

The data set is \(92, 82, 76, 83, 56, 57, 60, 98, 83, 95, 89, 76, 57, 94, 70, 69, 86, 64, 69, 56, 57, 63, 55, 63, 75, 98\). The minimum value \(x_{\min}=55\).

Step2: Determine the lower - class limit of the first class

Usually, we take the minimum value as the lower - class limit of the first class. So, the lower - class limit of the first class \(L = 55\).

Step3: Calculate the upper - class limit of the first class

The formula for the upper - class limit \(U\) of a class is \(U = L+(w - 1)\), where \(w\) is the class width. Given \(w = 9\) and \(L = 55\), then \(U=55+(9 - 1)=63\).

Answer:

\(63\)