Question

question 5
the density of gold can be given by the rate of 19.300 kg/m³. if 1 kg = 1000 grams and 1 meter (m) = 100 cm, give the density of gold in grams per cubic centimeter (g/cm³)

Explanation:

Step1: Convert units of mass

We know that \(1\space kg = 1000\space g\). So, \(19300\space kg/m^{3}=\frac{19300\times1000\space g}{1\space m^{3}}\)

Step2: Convert units of volume

Since \(1\space m = 100\space cm\), then \(1\space m^{3}=(100\space cm)^{3}=100^{3}\space cm^{3} = 1000000\space cm^{3}\)

Step3: Calculate density in \(g/cm^{3}\)

Density \(
ho=\frac{19300\times1000\space g}{1000000\space cm^{3}}\)

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Answer:

\(19.3\space g/cm^{3}\)