Question

question ava is the oldest of four siblings whose ages are consecutive odd integers. if the sum of their ages is 104, find avas age.

Explanation:

Step1: Let the ages of siblings

Let the ages of the four siblings (consecutive odd integers) be $x - 6$, $x - 4$, $x - 2$, $x$. Since Ava is the oldest, Ava's age is $x$.

Step2: Set up the sum - equation

The sum of their ages is $(x - 6)+(x - 4)+(x - 2)+x=104$.
Combining like - terms, we get $4x-12 = 104$.

Step3: Solve the equation for $x$

Add 12 to both sides of the equation: $4x-12 + 12=104 + 12$, which simplifies to $4x=116$.
Divide both sides by 4: $x=\frac{116}{4}=29$.

Answer:

29