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question 94
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round 12.996 to the nearest hundredth
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question 95
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round 1,012.01056 to the nearest hundredth
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question 96
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convert \\(\frac{3}{25}\\) to decimal form. rounding off to the nearest tenth if necessary.
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Question 94
Step1: Identify the hundredth and thousandth digits
The number is \(12.996\). The hundredth digit is \(9\) (second decimal place), and the thousandth digit is \(6\) (third decimal place).
Step2: Apply rounding rule
Since the thousandth digit (\(6\)) is greater than or equal to \(5\), we round up the hundredth digit. Rounding up \(9\) in the hundredth place causes a carryover: \(12.99 + 0.01 = 13.00\) (because \(99\) hundredths + \(1\) hundredth = \(100\) hundredths = \(1\) whole, so we add \(1\) to the tenths place as well, and so on).
Step1: Identify the hundredth and thousandth digits
The number is \(1012.01056\). The hundredth digit is \(1\) (second decimal place), and the thousandth digit is \(0\) (third decimal place).
Step2: Apply rounding rule
Since the thousandth digit (\(0\)) is less than \(5\), we leave the hundredth digit as it is. So we keep the number up to the hundredth place: \(1012.01\).
Step1: Divide numerator by denominator
To convert \(\frac{3}{25}\) to a decimal, we perform the division: \(3\div25\).
\(3\div25 = 0.12\)
Step2: Check if rounding to nearest tenth is needed
The decimal \(0.12\) to the nearest tenth: the tenths digit is \(1\), and the hundredths digit is \(2\) (which is less than \(5\)), so we leave the tenths digit as is. So \(0.12\) rounded to the nearest tenth is \(0.1\)? Wait, no—wait, \(0.12\) is already precise, but let's check the division again. Wait, \(3\div25\): \(25\times0.1 = 2.5\), \(3 - 2.5 = 0.5\), \(0.5\div25 = 0.02\), so \(0.1 + 0.02 = 0.12\). To the nearest tenth, \(0.12\) is \(0.1\)? Wait, no—wait, the tenths place is \(1\), hundredths is \(2\). Since \(2 < 5\), we round down, so \(0.1\)? Wait, no, wait: the question says "rounding off to the nearest tenth if necessary". But \(0.12\) is the exact decimal. Wait, maybe I made a mistake. Wait, \(3\div25\): \(25\times0.12 = 3\), so it's exactly \(0.12\). To the nearest tenth, \(0.12\) is \(0.1\)? Wait, no—tenth is one decimal place. \(0.12\) rounded to one decimal place: look at the second decimal place, which is \(2\) (less than \(5\)), so we keep the first decimal place as \(1\). So \(0.1\)? Wait, no, wait: \(0.12\) is closer to \(0.1\) than \(0.2\)? Wait, \(0.12 - 0.1 = 0.02\), \(0.2 - 0.12 = 0.08\), so yes, closer to \(0.1\). But wait, the exact decimal is \(0.12\), which is two decimal places. The question says "rounding off to the nearest tenth if necessary". So since \(0.12\) has more than one decimal place, we round to the nearest tenth. So \(0.12\) rounded to the nearest tenth is \(0.1\)? Wait, no, wait—wait, \(0.12\) is \(0.1\) when rounded to the nearest tenth? Wait, no, tenth is one decimal place. \(0.12\): the first decimal is \(1\), second is \(2\). Since \(2 < 5\), we don't round up, so it's \(0.1\). But wait, maybe the question considers that if the decimal is exact to more places, but we just need to present it as a decimal, maybe the exact value is acceptable. Wait, let's re - check the division: \(3\div25 = 0.12\). So the decimal form is \(0.12\), and to the nearest tenth, it's \(0.1\)? Wait, no, the question says "rounding off to the nearest tenth if necessary". So if the decimal has more than one decimal place, we round to the nearest tenth. But \(0.12\) is two decimal places. So rounding to the nearest tenth: look at the hundredths place (2), which is less than 5, so we keep the tenths place as 1. So \(0.1\)? Wait, no, that's incorrect. Wait, \(0.12\) is \(0.1\) when rounded to the nearest tenth? Wait, no, \(0.12\) is closer to \(0.1\) than \(0.2\), yes. But wait, maybe the question doesn't require rounding because \(0.12\) is already a decimal, and maybe "if necessary" means if the decimal is a repeating decimal or has more places, but here it's terminating. Wait, let's check the division again: \(3\div25\). \(25\times0.1 = 2.5\), \(3 - 2.5 = 0.5\), \(0.5\div25 = 0.02\), so \(0.1 + 0.02 = 0.12\). So the decimal is \(0.12\), and to the nearest tenth, it's \(0.1\)? Wait, no, the tenth place is the first decimal, so \(0.12\) rounded to the nearest tenth is \(0.1\)? Wait, no, that's wrong. Wait, \(0.12\) is \(0.1\) when rounded to one decimal place? Wait, no, \(0.12\) is \(0.1\) (tenth) because the hundredth digit is 2, which is less than 5. So we round down. So the decimal form is \(0.12\), and rounded to the nearest tenth is \(0.1\). But wait, maybe the question just wants the exact decimal, which is \(0.12\), and since it's already a decimal, no rounding is necessary? Wait, the question says "rounding off to…
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\(13.00\)