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Question
question 2 of 40
solve $2x - 8 \geq 22 - 4x$.
a. $x \leq 5$
b. $x \leq -15$
c. $x \geq -15$
d. $x \geq 5$
Step1: Add 4x to both sides
$2x - 8 + 4x \geq 22 - 4x + 4x$
$6x - 8 \geq 22$
Step2: Add 8 to both sides
$6x - 8 + 8 \geq 22 + 8$
$6x \geq 30$
Step3: Divide by 6
$\frac{6x}{6} \geq \frac{30}{6}$
$x \geq 5$
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D. $x\geq 5$