Question

question 8/30
¿cuántos (*) imprime el siguiente código en la consola?
flcor = 0
while floor < 6:
floor += 3
print (\*\. end= \\)
else:
print (\*\)
una
tres
déco
cara el código no genera salida)

Explanation:

To solve this, we analyze the code step by step:

Step 1: Initialization

We start with floor = 0.

Step 2: Entering the while loop

The condition for the while loop is while floor < 6:. Initially, floor is 0, which is less than 6, so we enter the loop.

Step 3: First iteration of the while loop

• Inside the loop, we have floor += 3. So floor becomes \( 0 + 3 = 3 \).
• Then we execute print("", end=""). This prints one (but we don't move to a new line because of end="").
• Now we check the loop condition again. floor = 3 which is still less than 6, so we enter the loop again.

Step 4: Second iteration of the while loop

• Inside the loop, we have floor += 3. So floor becomes \( 3 + 3 = 6 \).
• Then we execute print("", end=""). This prints another (still no new line).
• Now we check the loop condition again. floor = 6 which is not less than 6, so we exit the loop.

Step 5: After the while loop

We have print(""). This prints a third (and moves to a new line, but we are only concerned with the number of * printed).

Now we count the number of * printed:

• First print("", end="") → 1
• Second print("", end="") → 2 s (total)
• Third print("") → 3 s (total)

Step1: Inicializar floor = 0

floor = 0

Step2: Entrar en while (floor < 6)

while floor < 6:

Step3: Primer ciclo: floor = 0 + 3 = 3, imprimir *, floor = 3 < 6

floor += 3 → 3; print("*", end="")

Step4: Segundo ciclo: floor = 3 + 3 = 6, imprimir *, floor = 6 no < 6

floor += 3 → 6; print("*", end="")

Step5: Después del while: imprimir *

print("*")

Step6: Contar los * impresos

Se imprimen 3 * (uno en cada print).

Answer:

tres