Question

question 28 of 39
what is the area of a rectangle with vertices at (4, 3), (11, 3), (11, 9), and (4,
9)?
a. 26 units²
b. 21 units²
c. 13 units²
d. 42 units²

Explanation:

Step1: Calculate the length of the rectangle

The length of the rectangle can be found by the difference in the \(x -\)coordinates of two adjacent vertices (since \(y -\)coordinates are the same for these two points \((4,3)\) and \((11,3)\)).
\(l=\vert11 - 4\vert=7\)

Step2: Calculate the width of the rectangle

The width of the rectangle can be found by the difference in the \(y -\)coordinates of two adjacent vertices (since \(x -\)coordinates are the same for these two points \((11,3)\) and \((11,9)\)).
\(w=\vert9 - 3\vert=6\)

Step3: Calculate the area of the rectangle

The area formula of a rectangle is \(A = l\times w\).
Substitute \(l = 7\) and \(w = 6\) into the formula: \(A=7\times6 = 42\)

Answer:

D. \(42\) units\(^{2}\)