Question

question 5 of 25 while competing in the olympics, an athlete hurls a discus with a velocity of 15 m/s at an angle of 20°. what is the horizontal component of the discuss velocity? a. 7.2 m/s b. 5.1 m/s c. 14.1 m/s d. 9.5 m/s

Explanation:

Step1: Recall velocity - component formula

The formula for the horizontal component of velocity $v_x$ is $v_x = v\cos\theta$, where $v$ is the magnitude of the velocity and $\theta$ is the angle with the horizontal.

Step2: Substitute given values

Given $v = 15$ m/s and $\theta=20^{\circ}$, we have $v_x=15\times\cos(20^{\circ})$.
Since $\cos(20^{\circ})\approx0.9397$, then $v_x = 15\times0.9397 = 14.0955\approx14.1$ m/s.

Answer:

C. 14.1 m/s