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solve the following: $2 \frac{1}{3} \div 1 \frac{5}{9} = a \frac{x}{y}$
solve for a=
solve for x=
solve for y=
question 25
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solve the following: $25 \div \frac{1}{100} = a$
solve for a=

Explanation:

Question 24

Step1: Convert mixed numbers to improper fractions

\(2\frac{1}{3}=\frac{2\times3 + 1}{3}=\frac{7}{3}\), \(1\frac{5}{9}=\frac{1\times9 + 5}{9}=\frac{14}{9}\)

Step2: Divide the fractions (multiply by reciprocal)

\(\frac{7}{3}\div\frac{14}{9}=\frac{7}{3}\times\frac{9}{14}\)

Step3: Simplify the multiplication

\(\frac{7\times9}{3\times14}=\frac{63}{42}=\frac{3}{2}=1\frac{1}{2}\)

Step4: Identify \(A\), \(x\), \(y\)

From \(1\frac{1}{2}\), \(A = 1\), \(x = 1\), \(y = 2\)

Step1: Divide by a fraction (multiply by reciprocal)

\(25\div\frac{1}{100}=25\times100\)

Step2: Calculate the product

\(25\times100 = 2500\)

Answer:

\(A = 1\)
\(x = 1\)
\(y = 2\)

Question 25