Question

question 23 (1 point) saved a lightweight object and a very heavy object are sliding with equal speeds along a level frictionless surface. they both slide up the same frictionless hill with no air resistance. which object rises to a greater height? a) the light object because gravity slows it down less. b) the heavy object because it has more mass to carry it up the hill. c) the heavy object because it has greater initial kinetic energy. d) the lightweight object because the force of gravity on it is less. e) none of the statements is correct.

Explanation:

Step1: Apply conservation of mechanical energy

The initial kinetic energy \(K = \frac{1}{2}mv^{2}\) is converted into gravitational potential energy \(U = mgh\) at the maximum height. So, \(\frac{1}{2}mv^{2}=mgh\).

Step2: Solve for height \(h\)

Cancel out the mass \(m\) from both sides of the equation \(\frac{1}{2}mv^{2}=mgh\). We get \(h=\frac{v^{2}}{2g}\).

Answer:

e) None of the statements is correct.