Question

question 15 2 pts the weights of pumpkins grown at an ohio farm follow a normal distribution with a mean of 18.6 pounds and a standard deviation of 4.3 pounds. a pumpkin that weighs 27.6 pounds is ______ standard deviations away from the mean. as you engage in your calculations, round your answer to exactly one decimal place and enter this numerical answer in the text box below.

Explanation:

Step1: Identify the formula for z - score

The formula for the number of standard - deviations (z - score) a data point $x$ is from the mean $\mu$ is $z=\frac{x - \mu}{\sigma}$, where $\sigma$ is the standard deviation.

Step2: Substitute the given values

We are given that $\mu = 18.6$, $\sigma=4.3$, and $x = 27.6$. Substitute these values into the formula: $z=\frac{27.6 - 18.6}{4.3}$.

Step3: Calculate the numerator

$27.6−18.6 = 9$.

Step4: Calculate the z - score

$z=\frac{9}{4.3}\approx2.1$.

Answer:

$2.1$