Question

question 14
1 pts
a professional alligator handler is shopping for boots. she wants to get boots with a coefficient of static friction large enough to keep her stationary if she is pulled by a force of 900 newtons horizontally. she has a mass of 80 kg. what is the minimum static friction coefficient she needs for her boots?
0.36
1.15
2.12
0.87
0.65
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Explanation:

Step1: Calculate normal force

The normal force \(N\) on a horizontal surface is \(N = mg\), where \(m = 80\space kg\) and \(g=9.8\space m/s^{2}\).
\(N=80\times9.8 = 784\space N\)

Step2: Use static - friction formula

The maximum static - friction force \(f_s=\mu_sN\). To keep stationary, \(f_s\geq F\) (where \(F = 900\space N\)). So \(\mu_s=\frac{F}{N}\)
Substitute \(F = 900\space N\) and \(N = 784\space N\) into the formula: \(\mu_s=\frac{900}{784}\approx1.15\)

Answer:

\(1.15\)