Question

question 12 kay has an 80% probability of making a free throw in basketball, and each free throw is independent. kay gets to take 2 free throws and must make both to win the game. what is the probability that kays team will win the game? a 64% b 80% c 88% d 160% (so 100%) 5 points

Explanation:

Step1: Identify the probability of a single free - throw

The probability of making a single free - throw is $p = 0.8$.

Step2: Use the multiplication rule for independent events

Since the two free - throws are independent, the probability of making both is the product of the probabilities of making each one. Let $P(A\cap B)$ be the probability of making both free - throws. For independent events $A$ and $B$, $P(A\cap B)=P(A)\times P(B)$. Here, $P(A) = P(B)=0.8$. So $P(A\cap B)=0.8\times0.8 = 0.64$ or $64\%$.

Answer:

$64\%$ (B. 64%)