Question

question 12 (01.03 mc) the perimeter of a rectangle can be found using the equation p = 2l + 2w, where p is the perimeter, l is the length, and w is the width of the rectangle. can the perimeter of the rectangle be 64 units when its width is 11 units and its length is 20 units? (1 point) no. if the length is 20 and the width is 11, the perimeter is p = 20 + 22 = 42, not 64. no. if the length is 20 and the width is 11, the perimeter is p = 40 + 22 = 62, not 64. yes. if the perimeter is 64 units and the width is 11 units, then p + w is greater than 40. yes. if the perimeter is 64 units and the width is 11 units, then p + w is less than 40. question 13 (01.03 mc) artem and anthony are selling brownies at the school bake sale. anthony sold twice as many brownies as artem. together, they sold 15 brownies at the bake sale. could artem have sold 4 brownies? (1 point) yes, because 4 brownies is less than 15 brownies yes, because 2(4) brownies is less than 15 brownies no, because 2(4)+4 = 15 no, because 2(4)=15

Explanation:

Step1: Calculate perimeter for Question 12

Given $P = 2L+2W$, with $L = 20$ and $W = 11$. Substitute values: $P=2\times20 + 2\times11=40 + 22=62$.

Step2: Analyze Artem's sales for Question 13

Let the number of brownies Artem sold be $x$. Anthony sold $2x$ brownies. Then $x + 2x=15$, so $3x = 15$ and $x = 5$. If Artem sold 4 brownies, Anthony sold $2\times4 = 8$ brownies, and $4+8=12
eq15$.

Answer:

Question 12: No. If the length is 20 and the width is 11, the perimeter is $P = 40+22 = 62$, not 64.
Question 13: No, because $2(4)+4
eq15$