Question

question: 11
what will be printed to the screen if the inputs given to the program below are 1.2, -4, hi, 5?
def retrieve_positive_number():
while true:
try:
number = int(input(\enter a positive number: \))
if number > 0:
return number
print(\the number must be positive!\)
except valueerror:
print(\that wasnt a number!\)
print(retrieve_positive_number())

Explanation:

Step1: First input

The first input is \(1.2\). The function tries to convert it to an integer using int(). But \(1.2\) is a float. When using int(1.2), it truncates the decimal part, getting \(1\). But wait, no! Wait, the code has int(input(...)). The input function reads user input as a string. So when the input is \(1.2\), int("1.2") will raise a ValueError because you can't convert the string "1.2" (which has a decimal point) to an integer. So the except ValueError block is executed, and "That wasn't a number!" is printed.

Step2: Second input

The second input is \(- 4\). The code tries int("-4") which is \(-4\). Then checks if \(-4>0\). Since \(-4\) is not greater than \(0\), the code prints "The number must be positive!".

Step3: Third input

The third input is "hi". The code tries int("hi"), which raises a ValueError. So the except ValueError block is executed, and "That wasn't a number!" is printed.

Step4: Fourth input

The fourth input is \(5\). The code tries int("5") which is \(5\). Then checks if \(5 > 0\). Since \(5>0\), the function returns \(5\).

Answer:

5