Question

question 11 of 30
the side lengths of a 30 - 60 - 90 triangle are in the ratio 1:√3:2. what is sin60°?
oa. 1
ob.
oc.
od. √3

Explanation:

Step1: Recall sine definition

$\sin(\theta) = \frac{\text{opposite}}{\text{hypotenuse}}$

Step2: Assign sides for 30-60-90 triangle

Let sides be $1$ (opposite 30°), $\sqrt{3}$ (opposite 60°), $2$ (hypotenuse).

Step3: Calculate $\sin(60^\circ)$

$\sin(60^\circ) = \frac{\sqrt{3}}{2}$

Answer:

Assuming the intended correct option (likely misrendered as B or C in the image) is $\frac{\sqrt{3}}{2}$. If forced to choose from the given options (with possible rendering errors), the standard value is $\frac{\sqrt{3}}{2}$.