Question

question 6 of 10

roberto had $88, which is eleven times as much money as bianca had. how much money did bianca have? select the correct solution method below, representing biancas money with \\(x\\).

a. \\(x + 11 = 88\\). subtract 11 from both sides. bianca had $77.
b. \\(11x = 88\\). divide both sides by 11. bianca had $8.
c. \\(\frac{x}{11} = 88\\). multiply both sides by 11. bianca had $968.
d. \\(x - 11 = 88\\). add 11 to both sides. bianca had $99.

Explanation:

Set up the algebraic equation

$$ 11x = 88 $$

Solve for x using the division property of equality

$$
LATEXBLOCK0
$$

Answer:

• A. \(x + 11 = 88\). Subtract 11 from both sides. Bianca had $77.
• B. \(11x = 88\). Divide both sides by 11. Bianca had $8. (Correct answer)
• C. \(\frac{x}{11} = 88\). Multiply both sides by 11. Bianca had $968.
• D. \(x - 11 = 88\). Add 11 to both sides. Bianca had $99.