Question

question 10 (1 point)
an object moves 15.0 m north and then 11.0 m south. find both the distance traveled and the magnitude of the displacement vector.
4.0 m, 26.0 m
26.0 m, 4.0 m
26.0 m, 26.0 m
4.0 m, 4.0 m

Explanation:

Step1: Calculate the distance traveled

Distance is a scalar quantity. It is the total length of the path covered.
The object moves \(15.0\) m and then \(11.0\) m. So, \(d = 15.0+11.0\)
\(d=26.0\) m

Step2: Calculate the displacement

Displacement is a vector quantity. Let north be the positive direction.
The first displacement \(x_1 = 15.0\) m (north) and the second displacement \(x_2=- 11.0\) m (south).
The displacement \(x=x_1 + x_2\)
\(x=15.0+( - 11.0)\)
\(x = 4.0\) m

Answer:

B. \(26.0\) m, \(4.0\) m