Question

question 8 of 10
at a pizza shop, 70% of the customers order a pizza, 25% of the customers order a salad, and 15% of the customers order both a pizza and a salad.
if a customer is chosen at random, what is the probability that he or she orders either a pizza or a salad?
a. 0.80
b. 0.95
c. 0.45
d. 0.175

Explanation:

Step1: Recall the formula for \(P(A\cup B)\)

The formula for the probability of the union of two events \(A\) and \(B\) is \(P(A\cup B)=P(A)+P(B)-P(A\cap B)\). Let \(A\) be the event that a customer orders a pizza (\(P(A) = 0.7\)) and \(B\) be the event that a customer orders a salad (\(P(B)=0.25\)), and \(P(A\cap B) = 0.15\).

Step2: Substitute values into the formula

Substitute \(P(A)=0.7\), \(P(B) = 0.25\), and \(P(A\cap B)=0.15\) into \(P(A\cup B)=P(A)+P(B)-P(A\cap B)\). We get \(P(A\cup B)=0.7 + 0.25- 0.15\).

Step3: Calculate the result

\(0.7+0.25 - 0.15=(0.7+0.25)-0.15=0.95 - 0.15=0.8\).

Answer:

A. 0.80