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Question
question 6 of 10
on a piece of paper, draw a box plot to represent the data
below. then determine which answer choice matches the box
plot you drew.
11, 12, 13, 15, 17, 19, 22, 24, 29, 33, 38
a.
b.
c.
Step1: Find the median (Q2)
The data set is \(11, 12, 13, 15, 17, 19, 22, 24, 29, 33, 38\) (11 values). The median is the 6th value, so \(Q2 = 19\)? Wait, no, wait: 11 values, the middle is the 6th? Wait, 11 numbers: positions 1 - 11. The median (Q2) is at position \(\frac{11 + 1}{2}=6\), so the 6th value is \(19\)? Wait, no, let's list them: 1 (11), 2 (12), 3 (13), 4 (15), 5 (17), 6 (19), 7 (22), 8 (24), 9 (29), 10 (33), 11 (38). So median (Q2) is 19? Wait, no, wait, 11 numbers: the median is the 6th term? Wait, no, for odd number of observations, median is the \((n + 1)/2\)th term. So \(n = 11\), \((11 + 1)/2 = 6\), so 6th term is 19. Then, the lower half is the first 5 numbers: \(11, 12, 13, 15, 17\). The median of the lower half (Q1) is the 3rd term: 13. The upper half is the last 5 numbers: \(22, 24, 29, 33, 38\). The median of the upper half (Q3) is the 3rd term: 29. Wait, no, wait: lower half is first 5 (positions 1 - 5), so median of lower half is position 3: 13. Upper half is positions 7 - 11 (5 numbers), median is position 9: 29? Wait, no, positions 7 - 11: 7 (22), 8 (24), 9 (29), 10 (33), 11 (38). So median of upper half is 29. Wait, but let's check again. Wait, the data set is 11 numbers:
1: 11
2: 12
3: 13
4: 15
5: 17
6: 19 (median, Q2)
7: 22
8: 24
9: 29
10: 33
11: 38
So lower quartile (Q1) is the median of the first 5 numbers (11,12,13,15,17). The median of these 5 is the 3rd number: 13. Upper quartile (Q3) is the median of the last 5 numbers (22,24,29,33,38). The median of these 5 is the 3rd number: 29. The minimum is 11, maximum is 38.
Now, let's check the box plots:
- The box should have Q1 (13), Q2 (19), Q3 (29). Wait, no, wait, maybe I made a mistake. Wait, the data set: 11,12,13,15,17,19,22,24,29,33,38. Let's count the number of elements: 11. So median is the 6th element: 19. Then lower half is elements 1 - 5: 11,12,13,15,17. Median of lower half (Q1) is 13 (3rd element). Upper half is elements 7 - 11: 22,24,29,33,38. Median of upper half (Q3) is 29 (3rd element of upper half). So the box plot should have:
- Minimum: 11
- Q1: 13
- Q2: 19
- Q3: 29
- Maximum: 38
Now let's check the options:
Option A: The left whisker goes to 11 (min), Q1 is around 13? Wait, the first box starts at 12? No, wait the x-axis is 10,12,14,16,18,20,22,24,26,28,30,32,34,36,38,40. Wait, maybe the ticks are at 10,12,14,16,18,20,22,24,26,28,30,32,34,36,38,40. So let's see the box positions.
Wait maybe I miscalculated Q1, Q2, Q3. Let's use the formula for quartiles:
For a data set with n elements, the position of Q1 is \(\frac{n + 1}{4}\), Q2 is \(\frac{n + 1}{2}\), Q3 is \(\frac{3(n + 1)}{4}\).
n = 11, so:
Q1 position: \(\frac{11 + 1}{4}=3\), so 3rd element: 13 (correct, as before)
Q2 position: \(\frac{11 + 1}{2}=6\), 6th element: 19 (correct)
Q3 position: \(\frac{3(11 + 1)}{4}=9\), 9th element: 29 (correct)
So min = 11, Q1 = 13, Q2 = 19, Q3 = 29, max = 38.
Now let's check the box plots:
Option A: The left whisker (min) is at 11 (since the first line is at 11). The box starts at Q1 (13? Wait the first box's left edge is at 12? No, the x-axis ticks: 10,12,14,16,18,20,22,24,26,28,30,32,34,36,38,40. So between 10 and 12 is 11? Wait maybe the ticks are labeled at 10,12,14,... so the interval between ticks is 2. So 10,12 (11 is between 10 and 12), 14 (13 between 12 and 14), etc.
Wait Option C: The left whisker is at 11 (min), Q1 is at 13 (between 12 and 14), Q2 at 19 (between 18 and 20), Q3 at 29 (between 28 and 30), max at 38. Wait but let's check the box lengths.
Wait maybe I made a mistake in quartile calculatio…
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