Question

question 1 of 10
find the solutions to the equation below.
check all that apply.
$9x^2 - 81 = 0$
a. $x = -9$
b. $x = -3$
c. $x = 9$
d. $x = 3$
e. $x = 1$
f. $x = -81$

Explanation:

Step1: Isolate the \(x^2\) term

First, we add 81 to both sides of the equation \(9x^2 - 81 = 0\) to get \(9x^2 = 81\). Then, we divide both sides by 9, which gives \(x^2=\frac{81}{9} = 9\).

Step2: Solve for \(x\)

Taking the square root of both sides, we know that if \(x^2 = 9\), then \(x=\pm\sqrt{9}=\pm3\). So \(x = 3\) or \(x=- 3\).

Answer:

B. \(x = - 3\), D. \(x = 3\)