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question 2 of 10
an 80% confidence interval for a proportion is found to be (0.52, 0.56). what is the margin of error?
a. 0.02
b. 0.01
c. 0.04
d. 0.03
Step1: Find interval width
Width = Upper bound - Lower bound = $0.56 - 0.52 = 0.04$
Step2: Calculate margin of error
Margin of error = $\frac{\text{Width}}{2} = \frac{0.04}{2} = 0.02$
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A. 0.02