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quadrilateral uvwx is a rectangle, uw = 2c, and vx = c + 85. what is vx?

Question

quadrilateral uvwx is a rectangle, uw = 2c, and vx = c + 85. what is vx?

Explanation:

Step1: Use the property of rectangle diagonals

In a rectangle, the diagonals are equal. So, \(UW = VX\).
Given \(UW = 2c\) and \(VX=c + 85\), we set up the equation \(2c=c + 85\).

Step2: Solve the equation for \(c\)

Subtract \(c\) from both sides of the equation \(2c=c + 85\).
\(2c−c=c + 85−c\)
\(c = 85\).

Step3: Find the value of \(VX\)

Substitute \(c = 85\) into the expression for \(VX\). Since \(VX=c + 85\), then \(VX=85 + 85\).

Answer:

\(170\)