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put the following equation of a line into slope-intercept form, simplif…

Question

put the following equation of a line into slope-intercept form, simplifying all fractions. 8x + 6y = -6

Explanation:

Step1: Isolate the y-term

Subtract \(8x\) from both sides of the equation \(8x + 6y=-6\).
\(6y=-8x - 6\)

Step2: Solve for y

Divide every term by \(6\) to get \(y\) by itself.
\(y=\frac{-8x}{6}-\frac{6}{6}\)
Simplify the fractions. \(\frac{-8}{6}\) simplifies to \(-\frac{4}{3}\) and \(\frac{6}{6}=1\). So \(y = -\frac{4}{3}x-1\)

Answer:

\(y = -\frac{4}{3}x - 1\)