Question

punnett worksheet
complete this live worksheet. once finished, take screenshot of work and upload picture in box on right. i did the first one for you.

Explanation:

Identify the cross

We analyze the given Punnett square for body color.
The parent alleles are \(B\) and \(b\) on top, and \(b\) and \(b\) on the left.
This represents a cross between a heterozygous parent (\(Bb\)) and a homozygous recessive parent (\(bb\)).

Determine offspring genotypes

Using the Gametes from each parent, we fill the Punnett square:

• Top-left: \(Bb\)
• Top-right: \(bb\)
• Bottom-left: \(Bb\)
• Bottom-right: \(bb\)

Calculate genotype frequencies

We count the occurrences of each genotype among the 4 offspring cells:

• Heterozygous (\(Bb\)): 2 out of 4
• Homozygous Dominant (\(BB\)): 0 out of 4
• Homozygous Recessive (\(bb\)): 2 out of 4

Convert to percentages

We calculate the percentage for each genotype:

• Heterozygous: \(\frac{2}{4} = 50\%\)
• Homozygous Dominant: \(\frac{0}{4} = 0\%\)
• Homozygous Recessive: \(\frac{2}{4} = 50\%\)

Identify the error

The worksheet in the image shows incorrect values in the table:

• It lists Heterozygous as \(\frac{3}{4} = 75\%\).
• It lists Homozygous Recessive as \(\frac{1}{4} = 25\%\).

The correct values based on the Punnett square are \(50\%\) Heterozygous (\(Bb\)) and \(50\%\) Homozygous Recessive (\(bb\)).

Answer:

Based on the Punnett square shown in the worksheet:

• Heterozygous (\(Bb\)): \(\frac{2}{4} = 50\%\)
• Homozygous Dominant (\(BB\)): \(\frac{0}{4} = 0\%\)
• Homozygous Recessive (\(bb\)): \(\frac{2}{4} = 50\%\)

(Note: The values currently filled in the worksheet table in the image contain an error, as they list heterozygous as \(75\%\) and homozygous recessive as \(25\%\).)