QUESTION IMAGE
Question
proving a quadrilateral is a parallelogram
in parallelogram abcd, what is dc?
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Step1: Use the property of parallelogram
In a parallelogram, opposite sides are equal. So, \(AB = DC\). Given \(AB=(9x - 14)\) in and \(DC=(3x + 4)\) in. Then \(9x-14=3x + 4\).
Step2: Solve the equation for \(x\)
Subtract \(3x\) from both sides: \(9x-3x-14=3x-3x + 4\), which simplifies to \(6x-14 = 4\).
Add \(14\) to both sides: \(6x-14 + 14=4 + 14\), so \(6x=18\).
Divide both sides by \(6\): \(x=\frac{18}{6}=3\).
Step3: Find the length of \(DC\)
Substitute \(x = 3\) into the expression for \(DC\). \(DC=3x+4\).
\(DC=3\times3 + 4=9 + 4=13\) in.
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13 in.