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- a gasket requires 2/3 foot of material. how much material is needed for 6 gaskets?
- each gasket requires 3/4 foot of material. how much material is needed for 12 gaskets?
- a hose cut for repairs is 1/5 meter long. how much hose is needed for 20 repairs?
- a gasket requires 7/8 foot of material. how much material is needed for 8 gaskets?
- each repair requires 2/3 foot of hose. how much hose is needed for 15 repairs?
- each gasket requires 5/6 foot of material. how much material is needed for 9 gaskets?
- a hose piece is 3/1 meter. how much hose is needed for 30 repairs?
- each gasket uses 2/5 foot of material. how much material is needed for 25 gaskets?
- each repair requires 1/4 meter of hose. how much hose is needed for 16 repairs?
- a gasket requires 7/12 foot of material. how much is needed for 24 gaskets?
- a mechanic cuts 3/8 meter of hose per repair. how much hose is needed for 32 repairs?
- each gasket requires 9/10 foot of material. how much is needed for 10 gaskets?
- a mechanic uses 2/9 meter of hose per job. how much hose is needed for 27 jobs?
- each gasket requires 4/5 foot of material. how much is needed for 15 gaskets?
- a mechanic cuts 5/12 meter of hose for each job. how much hose is needed for 36 jobs?
Step1: Multiply the amount of material per - unit by the number of units
- For the first problem: The amount of material per gasket is $\frac{2}{3}$ foot and the number of gaskets is 6. So the calculation is $\frac{2}{3}\times6=\frac{2\times6}{3}=4$ feet.
- For the second problem: The amount of material per gasket is $\frac{3}{4}$ foot and the number of gaskets is 12. So $\frac{3}{4}\times12=\frac{3\times12}{4}=9$ feet.
- For the third problem: The length of hose per repair is $\frac{1}{5}$ meter and the number of repairs is 20. So $\frac{1}{5}\times20=\frac{1\times20}{5}=4$ meters.
- For the fourth problem: The amount of material per gasket is $\frac{7}{8}$ foot and the number of gaskets is 8. So $\frac{7}{8}\times8 = 7$ feet.
- For the fifth problem: The amount of hose per repair is $\frac{2}{3}$ foot and the number of repairs is 15. So $\frac{2}{3}\times15=\frac{2\times15}{3}=10$ feet.
- For the sixth problem: The amount of material per gasket is $\frac{5}{6}$ foot and the number of gaskets is 9. So $\frac{5}{6}\times9=\frac{5\times9}{6}=\frac{15}{2}=7.5$ feet.
- For the seventh problem: The length of hose per repair is 3 meters (since $\frac{3}{1}=3$) and the number of repairs is 30. So $3\times30 = 90$ meters.
- For the eighth problem: The amount of material per gasket is $\frac{2}{5}$ foot and the number of gaskets is 25. So $\frac{2}{5}\times25=\frac{2\times25}{5}=10$ feet.
- For the ninth problem: The length of hose per repair is $\frac{1}{4}$ meter and the number of repairs is 16. So $\frac{1}{4}\times16=\frac{1\times16}{4}=4$ meters.
- For the tenth problem: The amount of material per gasket is $\frac{7}{12}$ foot and the number of gaskets is 24. So $\frac{7}{12}\times24=\frac{7\times24}{12}=14$ feet.
- For the eleventh problem: The length of hose per repair is $\frac{3}{8}$ meter and the number of repairs is 32. So $\frac{3}{8}\times32=\frac{3\times32}{8}=12$ meters.
- For the twelfth problem: The amount of material per gasket is $\frac{9}{10}$ foot and the number of gaskets is 10. So $\frac{9}{10}\times10 = 9$ feet.
- For the thirteenth problem: The length of hose per job is $\frac{2}{9}$ meter and the number of jobs is 27. So $\frac{2}{9}\times27=\frac{2\times27}{9}=6$ meters.
- For the fourteenth problem: The amount of material per gasket is $\frac{4}{5}$ foot and the number of gaskets is 15. So $\frac{4}{5}\times15=\frac{4\times15}{5}=12$ feet.
- For the fifteenth problem: The length of hose per job is $\frac{5}{12}$ meter and the number of jobs is 36. So $\frac{5}{12}\times36=\frac{5\times36}{12}=15$ meters.
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