QUESTION IMAGE
Question
for problems 1-4, evaluate. 1. 90 - 52.3
Step1: Align the numbers by decimal
We have \( 90.0 - 52.3 \) (since 90 can be written as 90.0 to match the decimal places of 52.3).
Step2: Subtract the numbers
Subtract the tenths place: \( 0 - 3 \) is not possible, so we borrow 1 from the ones place. The 0 in the ones place (of 90.0) becomes 10 (after borrowing 1 from the tens place, making the tens place 8, the ones place 10). Then, the ones place 10 becomes 9 (after borrowing 1 for the tenths place), and the tenths place becomes \( 10 - 3=7 \).
Subtract the ones place: \( 9 - 2 = 7 \).
Subtract the tens place: \( 8 - 5 = 3 \).
So, \( 90.0 - 52.3=37.7 \).
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\( 37.7 \)