Question

problem2 a bicycle accelerates from rest to 9 m/s in 3 s. a car accelerated from 0 to 36 m/s in 6 s. which is faster?

Explanation:

Step1: Define initial and final velocities for bicycle

For the bicycle, $v_1 = 0$ m/s (starts from rest), $v_2=9$ m/s.

Step2: Calculate change in velocity for bicycle

$\Delta V_{bicycle}=v_2 - v_1=9 - 0=9$ m/s.

Step3: Calculate time - interval for bicycle

$\Delta t_{bicycle}=3$ s.

Step4: Calculate acceleration of bicycle

Using the formula $a=\frac{\Delta V}{\Delta t}$, $a_{bicycle}=\frac{\Delta V_{bicycle}}{\Delta t_{bicycle}}=\frac{9}{3}=3$ m/s².

Step5: Define initial and final velocities for car

For the car, $v_1 = 0$ m/s (starts from rest), $v_2 = 36$ m/s.

Step6: Calculate change in velocity for car

$\Delta V_{car}=v_2 - v_1=36 - 0=36$ m/s.

Step7: Calculate time - interval for car

$\Delta t_{car}=6$ s.

Step8: Calculate acceleration of car

Using the formula $a=\frac{\Delta V}{\Delta t}$, $a_{car}=\frac{\Delta V_{car}}{\Delta t_{car}}=\frac{36}{6}=6$ m/s².

Step9: Compare accelerations

Since $6>3$, the car has a greater acceleration.

Answer:

The car is faster.