QUESTION IMAGE
Question
problem 6 part b
here is the table from the previous screen.
how many digits will be in the decimal for the fraction \\(\frac{1}{256}\\)?
| fraction | decimal | number of digits in decimal |
|---|---|---|
| \\(\frac{1}{4}\\) | 0.25 | 2 |
| \\(\frac{1}{8}\\) | 0.125 | 3 |
| \\(\frac{1}{16}\\) | 0.0025 | 4 |
| \\(\frac{1}{32}\\) | 0.03125 | 5 |
Step1: Analyze the pattern
Observe the given fractions: $\frac{1}{2}=2^1$, decimal digits = 1; $\frac{1}{4}=2^2$, decimal digits = 2; $\frac{1}{8}=2^3$, decimal digits = 3; $\frac{1}{16}=2^4$, decimal digits = 4; $\frac{1}{32}=2^5$, decimal digits = 5. The pattern is that for $\frac{1}{2^n}$, the number of decimal digits is $n$.
Step2: Express 256 as a power of 2
We know that $256 = 2^8$ (since $2^8 = 256$). So the fraction $\frac{1}{256}=\frac{1}{2^8}$.
Step3: Determine the number of digits
Using the pattern from Step 1, for $\frac{1}{2^n}$, the number of decimal digits is $n$. Here, $n = 8$, so the number of digits in the decimal for $\frac{1}{256}$ is 8.
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