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problem 20: (first taught in lesson 16) a supplement of an angle is twi…

Question

problem 20: (first taught in lesson 16) a supplement of an angle is twice as large as the angle. find the measure of the angle. after you enter your answer press go.

Explanation:

Step1: Define the angle

Let the angle be $x$.

Step2: Define its supplement

The supplement of the angle $x$ is $180 - x$.

Step3: Set up the equation

Since the supplement is twice as large as the angle, we have $180 - x=2x$.

Step4: Solve the equation

Add $x$ to both sides: $180=2x + x$, so $180 = 3x$. Then divide both sides by 3: $x=\frac{180}{3}=60$. So the measure of the angle is $60^{\circ}$.

Answer:

$60^{\circ}$