Question

(c) problem 19: (first taught in lesson 17) one angle of a linear pair is 12 less than half the other angle. find both angles. after you enter your answer press go. and

Explanation:

Step1: Define the variables

Let one angle be $x$ and the other be $y$.

Step2: Set up the equations

Since they are a linear - pair, $x + y=180$. Also, $x=\frac{y}{2}-12$.

Step3: Substitute and solve

Substitute $x=\frac{y}{2}-12$ into $x + y = 180$. We get $\frac{y}{2}-12+y=180$. Combine like - terms: $\frac{y}{2}+y=180 + 12$. $\frac{y + 2y}{2}=192$. $\frac{3y}{2}=192$. Multiply both sides by $\frac{2}{3}$: $y = 128$.

Step4: Find the other angle

Substitute $y = 128$ into $x + y=180$. So $x=180 - 128=52$.

Answer:

128, 52