Question

1. the probable fault in this circuit is

a r1 shorted

b c1 shorted

c there is no fault

d a changed value

Explanation:

To determine the circuit fault, analyze the voltage across R1 (0 V) and R2 (9.57 V). For a resistor in an AC circuit, voltage should exist if it's functioning. A shorted resistor (R1) would have 0 V across it (since it's bypassed, no voltage drop). The predicted current for R1 - related branch is 5.39 mA, and for R2 is 9.57 mA. If R1 were shorted, its resistance is 0, so the voltage across it is 0 (consistent with the 0 V measurement), while R2 (1 kΩ) has voltage (9.57 V, so \( I=\frac{V}{R}=\frac{9.57\,\text{V}}{1\,\text{kΩ}} = 9.57\,\text{mA}\), matching predicted). Options b (C1 shorted would affect AC but R1 voltage would not be 0 in a non - shorted R1 case), c (no fault would mean R1 has voltage drop), and d (changed value is less likely as 0 V implies short, not just value change) are inconsistent. So the probable fault is R1 shorted.

Answer:

a. R1 shorted