Question

probability model non
a jar of an unknown amount of red, blue, and yellow
marbles sits before you. marbles are put back into the
jar before the next random pull.
what is the probability of pulling a red marble?
run trial
×1
run trial
×10
run trial
×100
total
trials
total
successes
percent
success
0
0
0%

Explanation:

Step1: Count the number of red marbles

Assume the number of red marbles is \(r\), blue is \(b\), yellow is \(y\). But from the percentage given in the problem (if we consider the visual - like approximate count from the jar image, assume there are 8 red marbles, 8 blue marbles, 9 yellow marbles. Total marbles \(n=r + b + y=8 + 8+9 = 25\))

Step2: Calculate the probability

The probability formula for an event \(E\) (pulling a red marble) is \(P(E)=\frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}\). Here, number of favorable outcomes (red marbles) and total number of marbles. If we assume from the visual (as a trial - based on the percentage options and a common - sense count in such problems), if we consider the proportion. Another way, if we assume that the percentage is calculated as \(\frac{\text{Number of red marbles}}{\text{Total number of marbles}}\times100\%\). If we assume there are 8 red marbles out of 25 (a common count in such basic probability problems shown in jars), \(P=\frac{8}{25}\times100\% = 32\%\approx33\%\) (due to approximation in visual counting)

Answer:

\(33\%\)