Question

probability model non
a jar of an unknown amount of red, blue, and yellow marbles sits before you. marbles are put back into the jar before the next random pull.
what is the probability of pulling a red marble?
run trial
×1
run trial
×10
run trial
×100
total trials
0
total successes
0
percent success
0%

Explanation:

Step1: Count the marbles

Count the number of red marbles and the total number of marbles. Assume there are \(r\) red marbles and \(t\) total marbles.

Step2: Calculate probability

The probability \(P\) of pulling a red marble is \(P=\frac{r}{t}\). If we assume from the visual (counting red marbles as 4, blue as 5, yellow as 6, total \(4 + 5+6=15\)), then \(P=\frac{4}{15}\approx 26.67\%\), but since we have options, if we assume a different count (maybe in the simulation context, if we run trials and get proportion). But if we go by the formula \(P=\frac{\text{Number of red marbles}}{\text{Total number of marbles}}\). If we assume from the visual (count red as 5, blue as 5, yellow as 5, total 15), then \(P = \frac{5}{15}=\frac{1}{3}\approx33\%\)

Answer:

33%