Question

practice it!
select the statement that accurately interprets the distance-time graph.
karina took her dog for a walk to the park. she set off slowly and then increased her pace. at the park, karina turned around and walked slowly back home.
karina rode her bike east from her home up a steep hill. after a while, the slope of the hill decreased. once she reached the top of the hill, she raced down the other side.
karina went for a jog. she ran at a steady pace for some distance. at the end of her road, she bumped into a friend and her pace slowed to a walk. when karina left her friend, she walked quickly back home.
karina took the city bus to the library. when she got on, the bus traveled at a constant speed. the bus stopped to pick someone else up. then the bus stopped at the library and karina got off.
graph: distance from home (y-axis) vs time (x-axis), showing a graph with three segments: steep upward slope, less steep upward slope, steep downward slope to (0,0)

Explanation:

1. Analyze the first option: The graph has a steep initial increase (fast start), then a less steep increase (slower), then a steep decrease (fast return). But the first option says she set off slowly (should be shallow slope first) then increased pace (steeper), then slow return (shallow decrease). Doesn't match.
2. Analyze the second option: The graph's last segment is a steep decrease (racing down), but the option's last part is racing down, but the first two segments: first steep (up steep hill), then less steep (slope decreased), then steep down. Wait, but the graph's first segment is steep, second less steep, third steep down. But the option's direction is east, then top, then down. However, the distance - time graph's last segment brings distance back to zero (returning home), while this option doesn't mention returning home. So no.
3. Analyze the third option: First, steady pace (constant slope) - but the first segment is steep (fast), then less steep (slower, like walking after jogging), then steep decrease (quickly back home). Wait, the first part: she ran at steady pace (constant slope), but the first segment is steep (fast), then less steep (slower, maybe walking after bumping into friend), then steep decrease (quickly back home). Wait, the graph: starts at home (distance 0), first segment steep (fast), second less steep (slower), third steep down (fast return to home). The third option: jog (steady pace - but first segment is steep, maybe jogging fast? Then bumped into friend, pace slowed (less steep), then walked quickly back (steep down). And at the end, distance back to home. This matches the graph's structure: increasing distance (two segments, first steep, second less steep) then decreasing distance (steep) back to zero.
4. Analyze the fourth option: The bus stops would mean flat segments (constant time, constant distance) for picking up and at library. But the graph has no flat segments. So this is out.

Answer:

Karina went for a jog. She ran at a steady pace for some distance. At the end of her road, she bumped into a friend and her pace slowed to a walk. When Karina left her friend, she walked quickly back home.