Question

practice - radical equations and applications
18 points possible answered: 13/18
question 16
a scuba diver has a rope connecting the dive boat to an anchor on the ocean floor. the rope is 6 ft long. the
water is 5 ft deep. how far is the anchor from a point directly below the boat?
question help: video

Explanation:

Step1: Apply Pythagorean theorem

Let the distance be \(x\). According to \(a^{2}+b^{2}=c^{2}\), here \(c = 6\) (rope length, hypotenuse), \(a = 5\) (water depth). So \(x^{2}+5^{2}=6^{2}\).

Step2: Solve for \(x\)

\(x^{2}=6^{2}-5^{2}=36 - 25=11\). Then \(x=\sqrt{11}\approx3.32\) (ft).

Answer:

\(\sqrt{11}\approx3.32\) (ft)