Question

g.pr.10.6 (mc)

at a casino, there is a wheel with the numbers 1-50. the game costs $5 per spin. if you spin and land on the numbers 1-4, you win $1. if you spin the number 5 or 6, you win $10, and if you spin and land on 50, you win $25. the probability of winning each prize is below. find the probability of losing the game (spinning 7-49).

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$$\begin{tabular}{|c|c|c|c|c|} \\hline \\text{number spun} & 1-5 & 5-7 & 50 & 7-49 \\\\ \\hline \\text{probability} & 0.3 & 0.06 & 0.02 & \\\\ \\hline \\end{tabular}$$

Explanation:

Sum the given probabilities of the other outcomes

$$ P(\text{Other Outcomes}) = 0.3 + 0.06 + 0.02 = 0.38 $$

Subtract the sum from 1 to find the missing probability

$$ P(7\text{--}49) = 1 - 0.38 = 0.62 $$

Answer:

At a casino, there is a wheel with the numbers 1-50. The game costs $5 per spin. If you spin and land on the numbers 1-4, you win $1. If you spin the number 5 or 6, you win $10, and if you spin and land on 50, you win $25. The probability of winning each prize is below. Find the probability of losing the game (spinning 7-49).

Number Spun	1-5	5-7	50	7-49