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the positive number r is 133.7% of the positive number s, and s is p% o…

Question

the positive number r is 133.7% of the positive number s, and s is p% of r. which of the following is closest to the value of p?
(a) 33.7
(b) 66.9
(c) 74.8
(d) 133.7

Explanation:

Step1: Translate the problem into equations

We know that \( r \) is \( 133.7\% \) of \( s \), so mathematically, \( r = 1.337s \) (since \( 133.7\%=\frac{133.7}{100} = 1.337 \)). Also, \( s \) is \( p\% \) of \( r \), so \( s=\frac{p}{100}r \).

Step2: Substitute \( r \) from the first equation into the second

Substitute \( r = 1.337s \) into \( s=\frac{p}{100}r \). We get \( s=\frac{p}{100}(1.337s) \). Since \( s \) is a positive number, we can divide both sides by \( s \) (because \( s
eq0 \)). This gives \( 1=\frac{p}{100}(1.337) \).

Step3: Solve for \( p \)

Now, solve for \( p \). Multiply both sides by \( 100 \) and then divide by \( 1.337 \). So \( p=\frac{100}{1.337} \). Calculate this value: \( \frac{100}{1.337}\approx74.8 \).

Answer:

C. 74.8